x^2+62x+672=0

Solution for x^2+62x+672=0 equation:

x^2+62x+672=0

a = 1; b = 62; c = +672;
Δ = b2-4ac
Δ = 622-4·1·672
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-34}{2*1}=\frac{-96}{2}
=-48
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+34}{2*1}=\frac{-28}{2}
=-14
$